Talk:Poison

From Eternal Lands Wiki

--This is a work in progress by Ilobypie. Please do not make major edits until there is a new message saying it's done, or at least at a beta :) Thank you. -6/9/08

--Kk, beta is out, please proofread and fix if needs be :) - 6/11/08

-- Shows the need for LaTeX to be enabled in the wiki (see my request on forums). I can get you better looking formulas from LaTeX2HTML if you want.

-- The table should be done as a wiki/html table, imo. You should be able to export it from your spreadsheet program as csv (comma separated values), setting the separator to || and newlines to |-| , then add header and beginning and end by hand (or just copy the whole thing by hand). --Ermabwed 20:27, 12 June 2008 (UTC)

--I'll give these both a try when i get a minute later today :) Thank you for the tip. --Ilobypie.

--First goes right over my head, as for the csv, i have it saved as a csv file, how does that help me? The wiki has no open csv option as far as i can tell

-- open the csv-file with an editor (such as notepad if you're on windows), the contents should (almost) look like the source of a wiki table. You can then copy it to the wiki-editor window and apply some finishing touches (such as beginning and end of the table and header, rest should be working). --Ermabwed 05:48, 14 June 2008 (UTC)

-- can you add some insight as to how you get to the formula for poison total (should use a different letter than P for it, as you used that already for poison at a certain time, could be TP(k) (total poison for k simultaneous poisons). I figured the 51 = 6+3*5+3*4+3*2+3*2+3*2+3*1... your current formula can be simplified to read (using k for the number of poisons):

k*51 + 108* (k-1)*k/2 = k * (51 + 54*(k-1))

using the fact that the sum of the first n natural numbers is n*(n+1)/2 (see here for example). Thanks. --Ermabwed 07:03, 14 June 2008 (UTC)

--I like the current format, i think it's a bit more readable. As for the hows, i had this table for damages of that many poisons at a given time:

1=53 2=212 3=479 4=854 5=1337 6=1928 7=2627 8=3434 9=4349 10=5372 I then found the differences between each 0-1=53 1-2=159 2-3=267 3-4=375 4-5=483 5-6=591 6-7=699 7-8=807 8-9=915 9-10=1023 Changing 0-1 to 51, you get a constant difference of 108. Therefore you can write it as that sum, and then add 2(I noted by trial and error, all of the damages were off by 2, not just the first).

--All right. Image done and table done. I see your point on the second formula.. easier to plug in. I'll include both :) TY for the feedback. I believe this should bring the page out of beta :)